Calculate the emf of the following cell at 298 K ? Fe(s)|Fe^2 + (0.001 M )||H^+(1M)|H2(g) (1 bar), Pt(s) (Given: E^∘cell = + 0.44 V )
![Wavelength and Frequency E = h c = c = speed of light (3 x 10 8 m/s) = frequency (s -1 ) = wavelength (m) E = energy (Joules or J) h = Planck's constant. - ppt download Wavelength and Frequency E = h c = c = speed of light (3 x 10 8 m/s) = frequency (s -1 ) = wavelength (m) E = energy (Joules or J) h = Planck's constant. - ppt download](https://images.slideplayer.com/26/8733366/slides/slide_3.jpg)
Wavelength and Frequency E = h c = c = speed of light (3 x 10 8 m/s) = frequency (s -1 ) = wavelength (m) E = energy (Joules or J) h = Planck's constant. - ppt download
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